What is 2x-5y-16=0,3x+4y-1=0 ?

The solution to 2x-5y-16=0,3x+4y-1=0 is x=3,y=-2

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2x-5y-16=0,3x+4y-1=0

2 x - 5 y - 16 = 0, 3 x + 4 y - 1 = 0

x = 3, y = - 2

Solution steps

[2 x - 5 y - 16 = 0 3 x + 4 y - 1 = 0]

Isolate

x

for

2 x - 5 y - 16 = 0 : x = \frac{5 y + 16}{2}

Substitute

x = \frac{5 y + 16}{2}

[3 \cdot \frac{5 y + 16}{2} + 4 y - 1 = 0]

Simplify

[\frac{23 y + 48}{2} - 1 = 0]

Isolate

y

for

\frac{23 y + 48}{2} - 1 = 0 : y = - 2

For

x = \frac{5 y + 16}{2}

Substitute

y = - 2

x = \frac{5 ( - 2 ) + 16}{2}

\frac{5 ( - 2 ) + 16}{2} = 3

x = 3

The solutions to the system of equations are:

x = 3, y = - 2

x - y = 55, x + y = 110

2 x - 3 y = 2, 3 x + 4 y = 20

5 x = 80, \frac{0}{5} x = 36, x = 18

2 x + 3 y = 4, 3 x - 3 y = - 9

15 x - 7 y = 66, 7 x + 2 y = 15