What is 3x+4y=-1,3x-y=3 ?

The solution to 3x+4y=-1,3x-y=3 is x= 11/15 ,y=-4/5

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3x+4y=-1,3x-y=3

3 x + 4 y = - 1, 3 x - y = 3

x = \frac{11}{15}, y = - \frac{4}{5}

Solution steps

[3 x + 4 y = - 1 3 x - y = 3]

Isolate

x

for

3 x + 4 y = - 1 : x = \frac{- 1 - 4 y}{3}

Substitute

x = \frac{- 1 - 4 y}{3}

[3 \cdot \frac{- 1 - 4 y}{3} - y = 3]

Simplify

[- 1 - 5 y = 3]

Isolate

y

for

- 1 - 5 y = 3 : y = - \frac{4}{5}

For

x = \frac{- 1 - 4 y}{3}

Substitute

y = - \frac{4}{5}

x = \frac{- 1 - 4 ( - \frac{4}{5} )}{3}

\frac{- 1 - 4 ( - \frac{4}{5} )}{3} = \frac{11}{15}

x = \frac{11}{15}

The solutions to the system of equations are:

x = \frac{11}{15}, y = - \frac{4}{5}

2 x + 3 y + b = 0, 4 x = 3 y

2 x - y = 4, x + y = 2

x + y = 9, x - y = 5

x + y = 9, x - y = 3

- 7 x = 8, 4 - 7 x = 84