What is (3)x+y=0,2x-y=9 ?

The solution to (3)x+y=0,2x-y=9 is x= 9/5 ,y=-27/5

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(3)x+y=0,2x-y=9

(3) x + y = 0, 2 x - y = 9

x = \frac{9}{5}, y = - \frac{27}{5}

Solution steps

[(3) x + y = 0 2 x - y = 9]

Isolate

x

for

(3) x + y = 0 : x = - \frac{y}{3}

Substitute

x = - \frac{y}{3}

[2 (- \frac{y}{3}) - y = 9]

Simplify

[- \frac{5 y}{3} = 9]

Isolate

y

for

- \frac{5 y}{3} = 9 : y = - \frac{27}{5}

For

x = - \frac{y}{3}

Substitute

y = - \frac{27}{5}

x = - \frac{- \frac{27}{5}}{3}

- \frac{- \frac{27}{5}}{3} = \frac{9}{5}

x = \frac{9}{5}

The solutions to the system of equations are:

x = \frac{9}{5}, y = - \frac{27}{5}

5 x - 2 y = 13, x = - 3 y + 6

4 x - 3 y = 6, 5 x + 2 y = 19

\frac{7}{( 3 x )} + \frac{2}{y} = 11, \frac{5}{( 2 x )} + \frac{3}{( 4 y )} = 9

a + b = 7, a - b = - 1

y = - 42 + 4 x, 4 x + 15 y = - 3