What is x+y/3 =4,x-y/4 =5 ?

The solution to x+y/3 =4,x-y/4 =5 is x= 32/7 ,y=-12/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x+y/3 =4,x-y/4 =5

x + \frac{y}{3} = 4, x - \frac{y}{4} = 5

x = \frac{32}{7}, y = - \frac{12}{7}

Solution steps

[x + \frac{y}{3} = 4 x - \frac{y}{4} = 5]

Isolate

x

for

x + \frac{y}{3} = 4 : x = 4 - \frac{y}{3}

Substitute

x = 4 - \frac{y}{3}

[4 - \frac{y}{3} - \frac{y}{4} = 5]

Simplify

[- \frac{7 y}{12} + 4 = 5]

Isolate

y

for

- \frac{7 y}{12} + 4 = 5 : y = - \frac{12}{7}

For

x = 4 - \frac{y}{3}

Substitute

y = - \frac{12}{7}

x = 4 - \frac{- \frac{12}{7}}{3}

4 - \frac{- \frac{12}{7}}{3} = \frac{32}{7}

x = \frac{32}{7}

The solutions to the system of equations are:

x = \frac{32}{7}, y = - \frac{12}{7}

z = 4 - i, w (z) = - 6 + 4 i

x + 3 y = 4, 2 x - y = 1

x - 2 y = - 4, y = 5 - x

x = x - x + 4, x = 13

x + y = 17, 4 x - y = 43

What is x+y/3 =4,x-y/4 =5 ?
The solution to x+y/3 =4,x-y/4 =5 is x= 32/7 ,y=-12/7