What is ((x+3))/y =2,((y+6))/x =-1 ?

The solution to ((x+3))/y =2,((y+6))/x =-1 is

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((x+3))/y =2,((y+6))/x =-1

\frac{( x + 3 )}{y} = 2, \frac{( y + 6 )}{x} = - 1

(x = - 5, y = - 1)

Solution steps

[\frac{( x + 3 )}{y} = 2 \frac{( y + 6 )}{x} = - 1]

Isolate

y

for

\frac{( x + 3 )}{y} = 2 : y = \frac{x + 3}{2}

Plug the solutions

y = \frac{x + 3}{2}

into

\frac{( y + 6 )}{x} = - 1

For

\frac{( y + 6 )}{x} = - 1

, subsitute

y

with

\frac{x + 3}{2} : x = - 5

Plug the solutions

x = - 5

into

\frac{( x + 3 )}{y} = 2

For

\frac{( x + 3 )}{y} = 2

, subsitute

x

with

- 5 : y = - 1

Verify solutions by plugging them into the original equations

Therefore, the final solution for

\frac{( x + 3 )}{y} = 2, \frac{( y + 6 )}{x} = - 1

(x = - 5, y = - 1)

0 k = \frac{1}{42}, x = 16

3 x - 2 y = 5, 2 x + 3 y = 17

3 x + y + 1 = 0, 2 x - 3 y + 8 = 0

l \cdot c \cdot m = 16, 8 h \cdot c \cdot f (c, h, a, b) = 1, 2 a - b = 60 a + b

x - 3 y = 3, 3 x - 9 y = 2

What is ((x+3))/y =2,((y+6))/x =-1 ?
The solution to ((x+3))/y =2,((y+6))/x =-1 is