What is 3x_{1}+x_{2}=-4,6x_{1}+2x_{2}=-8 ?

The solution to 3x_{1}+x_{2}=-4,6x_{1}+2x_{2}=-8 is x_{1}=(-4-x_{2})/3

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3x_{1}+x_{2}=-4,6x_{1}+2x_{2}=-8

3 x_{1} + x_{2} = - 4, 6 x_{1} + 2 x_{2} = - 8

x_{1} = \frac{- 4 - x _{2}}{3}

Solution steps

[3 x_{1} + x_{2} = - 4 6 x_{1} + 2 x_{2} = - 8]

Isolate

x_{1}

for

3 x_{1} + x_{2} = - 4 : x_{1} = \frac{- 4 - x _{2}}{3}

Substitute

x_{1} = \frac{- 4 - x _{2}}{3}

[6 \cdot \frac{- 4 - x _{2}}{3} + 2 x_{2} = - 8]

Simplify

[- 8 = - 8]

The solutions to the system of equations are:

x_{1} = \frac{- 4 - x _{2}}{3}

e = 12 v, r = 5 r, i = 2 a

x + 3 y = 14, 3 x + 2 y = 21

x = 2 y + 1, 2 x - 2 y = 4

\frac{4}{x} - y + \frac{1}{x} - y = 3, \frac{2}{x} - y - \frac{3}{x} + y = 5

5 x + 3 y = - 1, - 3 x + 4 y = - 24

What is 3x_{1}+x_{2}=-4,6x_{1}+2x_{2}=-8 ?
The solution to 3x_{1}+x_{2}=-4,6x_{1}+2x_{2}=-8 is x_{1}=(-4-x_{2})/3