What is (2x-3)/(4y)=3,x-4y+7=0 ?

The solution to (2x-3)/(4y)=3,x-4y+7=0 is

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(2x-3)/(4y)=3,x-4y+7=0

\frac{2 x - 3}{4 y} = 3, x - 4 y + 7 = 0

(x = - 24, y = - \frac{17}{4})

Solution steps

[\frac{2 x - 3}{4 y} = 3 x - 4 y + 7 = 0]

Isolate

y

for

\frac{2 x - 3}{4 y} = 3 : y = \frac{2 x - 3}{12}

Plug the solutions

y = \frac{2 x - 3}{12}

into

x - 4 y + 7 = 0

For

x - 4 y + 7 = 0

, subsitute

y

with

\frac{2 x - 3}{12} : x = - 24

Plug the solutions

x = - 24

into

\frac{2 x - 3}{4 y} = 3

For

\frac{2 x - 3}{4 y} = 3

, subsitute

x

with

- 24 : y = - \frac{17}{4}

Verify solutions by plugging them into the original equations

Therefore, the final solution for

\frac{2 x - 3}{4 y} = 3, x - 4 y + 7 = 0

(x = - 24, y = - \frac{17}{4})

5 x - y = 3, 5 x + y = 13

y + 10 x = 2 y + 16, x = 5

2 x + y = 6, 3 x - y = 18

2 x + y = 6, 3 x - y = 14

a = - 1, 7 b = + 15