What is (16)/x+y=8,x-y=0 ?

The solution to (16)/x+y=8,x-y=0 is

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(16)/x+y=8,x-y=0

\frac{16}{x} + y = 8, x - y = 0

(x = 4, y = 4)

Solution steps

[\frac{16}{x} + y = 8 x - y = 0]

Add the equations

\frac{16}{x} + y = 8

\frac{16}{x} + y + (x - y) = 8 + 0

Simplify

x + \frac{16}{x} = 8

Solve

x + \frac{16}{x} = 8 : x = 4

Plug the solutions

x = 4

into

\frac{16}{x} + y = 8

For

\frac{16}{x} + y = 8

, subsitute

x

with

4 : y = 4

Verify solutions by plugging them into the original equations

Therefore, the final solution for

\frac{16}{x} + y = 8, x - y = 0

(x = 4, y = 4)

4 m + 6 n = 54, 3 m + 2 n = 28

10 x - 9 y = 2, 4 y = x - 2

x = - 25, y = - 18

\frac{x}{- 4} = - 2, \frac{5}{y} = - \frac{35}{28}

- i + z^{2} = 1, + i - z^{3} = 2 + i, z^{1} = 1