What is 1/7 x+y/3 =5, x/2-y/9 =6 ?

The solution to 1/7 x+y/3 =5, x/2-y/9 =6 is x=14,y=9

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1/7 x+y/3 =5, x/2-y/9 =6

\frac{1}{7} x + \frac{y}{3} = 5, \frac{x}{2} - \frac{y}{9} = 6

x = 14, y = 9

Solution steps

[\frac{1}{7} x + \frac{y}{3} = 5 \frac{x}{2} - \frac{y}{9} = 6]

Isolate

x

for

\frac{1}{7} x + \frac{y}{3} = 5 : x = 35 - \frac{7 y}{3}

Substitute

x = 35 - \frac{7 y}{3}

[\frac{35 - \frac{7 y}{3}}{2} - \frac{y}{9} = 6]

Simplify

[\frac{315 - 23 y}{18} = 6]

Isolate

y

for

\frac{315 - 23 y}{18} = 6 : y = 9

For

x = 35 - \frac{7 y}{3}

Substitute

y = 9

x = 35 - \frac{7 \cdot 9}{3}

35 - \frac{7 \cdot 9}{3} = 14

x = 14

The solutions to the system of equations are:

x = 14, y = 9

3 x + 2 y = 5, x - 3 y = 9

3 x + 2 x + z = 6, 3 x + y + z = 5, x + y + z = 3

x + 2 y = 7, 2 x + 3 y = 0

6 x - 3 y + 10 = 0, 2 - y + 9 = 0

2 y - x = 8, 5 y - x = 1, 4 y - 2 x = 1

What is 1/7 x+y/3 =5, x/2-y/9 =6 ?
The solution to 1/7 x+y/3 =5, x/2-y/9 =6 is x=14,y=9