What is 7x+5y-3z=16,3x-5y+2z=-8,5x+3y-7z=0 ?

The solution to 7x+5y-3z=16,3x-5y+2z=-8,5x+3y-7z=0 is x=1,y=3,z=2

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7x+5y-3z=16,3x-5y+2z=-8,5x+3y-7z=0

7 x + 5 y - 3 z = 16, 3 x - 5 y + 2 z = - 8, 5 x + 3 y - 7 z = 0

x = 1, y = 3, z = 2

Solution steps

7 x + 5 y - 3 z = 16 3 x - 5 y + 2 z = - 8 5 x + 3 y - 7 z = 0

Isolate

x

for

7 x + 5 y - 3 z = 16 : x = \frac{16 - 5 y + 3 z}{7}

Substitute

x = \frac{16 - 5 y + 3 z}{7}

[3 \cdot \frac{16 - 5 y + 3 z}{7} - 5 y + 2 z = - 8 5 \cdot \frac{16 - 5 y + 3 z}{7} + 3 y - 7 z = 0]

Simplify

[\frac{- 50 y + 23 z + 48}{7} = - 8 \frac{- 4 y - 34 z + 80}{7} = 0]

Isolate

y

for

\frac{- 50 y + 23 z + 48}{7} = - 8 : y = - \frac{- 23 z - 104}{50}

Substitute

y = - \frac{- 23 z - 104}{50}

[\frac{- 4 ( - \frac{- 23 z - 104}{50} ) - 34 z + 80}{7} = 0]

Simplify

[\frac{128 ( - z + 2 )}{25} = 0]

Isolate

z

for

\frac{128 ( - z + 2 )}{25} = 0 : z = 2

For

y = - \frac{- 23 z - 104}{50}

Substitute

z = 2

y = - \frac{- 23 \cdot 2 - 104}{50}

- \frac{- 23 \cdot 2 - 104}{50} = 3

y = 3

For

x = \frac{16 - 5 y + 3 z}{7}

Substitute

y = 3, z = 2

x = \frac{16 - 5 \cdot 3 + 3 \cdot 2}{7}

Simplify

x = 1

The solutions to the system of equations are:

x = 1, y = 3, z = 2

9 x + 6 y = 8, 4 x - 2 y = 4

x + y = g (x, y), 8 x - y = 0

8 x + 4 y = - 4, 10 x - 4 y = 4

y = \frac{1}{( x ^{2} )}, x = 2, x = 3

- x + 2 y = 1, 2 x + 5 y = 25

What is 7x+5y-3z=16,3x-5y+2z=-8,5x+3y-7z=0 ?
The solution to 7x+5y-3z=16,3x-5y+2z=-8,5x+3y-7z=0 is x=1,y=3,z=2