What are the solutions to the equation z^2-12z=-11 ?

The solutions to the equation z^2-12z=-11 are z=11,z=1

Find the zeros of z^2-12z=-11

The zeros of z^2-12z=-11 are z=11,z=1

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z^{2} - 12 z = - 11

z = 11, z = 1

Solution steps

z^{2} - 12 z = - 11

Move

11

to the left side

z^{2} - 12 z + 11 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 11}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 11 = 10

z_{1, 2} = \frac{- ( - 12 ) \pm 10}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 12 ) + 10}{2 \cdot 1}, z_{2} = \frac{- ( - 12 ) - 10}{2 \cdot 1}

z = \frac{- ( - 12 ) + 10}{2 \cdot 1} : 11

z = \frac{- ( - 12 ) - 10}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

z = 11, z = 1

(\frac{x ^{2}}{y ^{2}})^{- 1}

\frac{- 2 z - 3}{3} < 5

\frac{x + 9}{2} \geq 9

507

(t - 1)^{2} = (t + 1)^{2} + 16

What are the solutions to the equation z^2-12z=-11 ?
The solutions to the equation z^2-12z=-11 are z=11,z=1
Find the zeros of z^2-12z=-11
The zeros of z^2-12z=-11 are z=11,z=1