What is 2x-7y=39,3x+5y=31 ?

The solution to 2x-7y=39,3x+5y=31 is x= 412/31 ,y=-55/31

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2x-7y=39,3x+5y=31

2 x - 7 y = 39, 3 x + 5 y = 31

x = \frac{412}{31}, y = - \frac{55}{31}

Solution steps

[2 x - 7 y = 39 3 x + 5 y = 31]

Isolate

x

for

2 x - 7 y = 39 : x = \frac{39 + 7 y}{2}

Substitute

x = \frac{39 + 7 y}{2}

[3 \cdot \frac{39 + 7 y}{2} + 5 y = 31]

Simplify

[\frac{117 + 31 y}{2} = 31]

Isolate

y

for

\frac{117 + 31 y}{2} = 31 : y = - \frac{55}{31}

For

x = \frac{39 + 7 y}{2}

Substitute

y = - \frac{55}{31}

x = \frac{39 + 7 ( - \frac{55}{31} )}{2}

\frac{39 + 7 ( - \frac{55}{31} )}{2} = \frac{412}{31}

x = \frac{412}{31}

The solutions to the system of equations are:

x = \frac{412}{31}, y = - \frac{55}{31}

8 x - 5 y = - 21, 7 y + 4 x = - 1

4 x + 3 y = 1, 8 e^{6} x + y = 13

126 x + 88 y = 18, 72 x + 48 y = 10

\frac{1}{2} x + y = 5, - \frac{1}{2} x + y = 3

5 x + 10 y = 50, x - y = 7

What is 2x-7y=39,3x+5y=31 ?
The solution to 2x-7y=39,3x+5y=31 is x= 412/31 ,y=-55/31