What are the solutions to the equation x=-3(x+7)(x-2) ?

The solutions to the equation x=-3(x+7)(x-2) are x=-(8+sqrt(190))/3 ,x=(sqrt(190)-8)/3

Find the zeros of x=-3(x+7)(x-2)

The zeros of x=-3(x+7)(x-2) are x=-(8+sqrt(190))/3 ,x=(sqrt(190)-8)/3

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x = - 3 (x + 7) (x - 2)

x = - \frac{8 + 190}{3}, x = \frac{190 - 8}{3}

Solution steps

x = - 3 (x + 7) (x - 2)

Expand

- 3 (x + 7) (x - 2) : - 3 x^{2} - 15 x + 42

x = - 3 x^{2} - 15 x + 42

Switch sides

- 3 x^{2} - 15 x + 42 = x

Move

x

to the left side

- 3 x^{2} - 16 x + 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 ( - 3 ) \cdot 42}{2 ( - 3 )}

(- 16)^{2} - 4 (- 3) \cdot 42 = 2190

x_{1, 2} = \frac{- ( - 16 ) \pm 2 190}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 190}{2 ( - 3 )}, x_{2} = \frac{- ( - 16 ) - 2 190}{2 ( - 3 )}

x = \frac{- ( - 16 ) + 2 190}{2 ( - 3 )} : - \frac{8 + 190}{3}

x = \frac{- ( - 16 ) - 2 190}{2 ( - 3 )} : \frac{190 - 8}{3}

The solutions to the quadratic equation are:

x = - \frac{8 + 190}{3}, x = \frac{190 - 8}{3}

(\frac{5}{2})^{- 2}

(x + 3) (x + 1) (x - 4) < 0

x^{2} - 5 x + 9 = 0

- 12 = 8 + 4 s

\frac{4}{5} + \frac{3}{4} \cdot \frac{1}{2} - \frac{2}{3}

What are the solutions to the equation x=-3(x+7)(x-2) ?
The solutions to the equation x=-3(x+7)(x-2) are x=-(8+sqrt(190))/3 ,x=(sqrt(190)-8)/3
Find the zeros of x=-3(x+7)(x-2)
The zeros of x=-3(x+7)(x-2) are x=-(8+sqrt(190))/3 ,x=(sqrt(190)-8)/3