What is 3x+2y-z=4,x+y+z=6,2x-y+z=3 ?

The solution to 3x+2y-z=4,x+y+z=6,2x-y+z=3 is x=1,y=2,z=3

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3x+2y-z=4,x+y+z=6,2x-y+z=3

3 x + 2 y - z = 4, x + y + z = 6, 2 x - y + z = 3

x = 1, y = 2, z = 3

Solution steps

3 x + 2 y - z = 4 x + y + z = 6 2 x - y + z = 3

Isolate

x

for

3 x + 2 y - z = 4 : x = \frac{4 - 2 y + z}{3}

Substitute

x = \frac{4 - 2 y + z}{3}

[\frac{4 - 2 y + z}{3} + y + z = 6 2 \cdot \frac{4 - 2 y + z}{3} - y + z = 3]

Simplify

[\frac{y + 4 z + 4}{3} = 6 \frac{- 7 y + 5 z + 8}{3} = 3]

Isolate

y

for

\frac{y + 4 z + 4}{3} = 6 : y = - 4 z + 14

Substitute

y = - 4 z + 14

[\frac{- 7 ( - 4 z + 14 ) + 5 z + 8}{3} = 3]

Simplify

[11 z - 30 = 3]

Isolate

z

for

11 z - 30 = 3 : z = 3

For

y = - 4 z + 14

Substitute

z = 3

y = - 4 \cdot 3 + 14

Simplify

y = 2

For

x = \frac{4 - 2 y + z}{3}

Substitute

y = 2, z = 3

x = \frac{4 - 2 \cdot 2 + 3}{3}

Simplify

x = 1

The solutions to the system of equations are:

x = 1, y = 2, z = 3

a = - 12, b = - \frac{8}{11}, c = - \frac{7}{12}

2 \frac{x}{x} - 3 + \frac{1}{2} x = 3, x + \frac{9}{( x - 3 )} (2 x + 3) = 0

2 x - 5 y = 1, 6 - 3 x + 6 y = 21

3 x - y = 35, 2 x - 3 y = 70

3 x + 2 y = 4, - 9 x - 6 y = 12

What is 3x+2y-z=4,x+y+z=6,2x-y+z=3 ?
The solution to 3x+2y-z=4,x+y+z=6,2x-y+z=3 is x=1,y=2,z=3