What is x+5y=1,6x+3y=10 ?

The solution to x+5y=1,6x+3y=10 is x= 47/27 ,y=-4/27

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x+5y=1,6x+3y=10

x + 5 y = 1, 6 x + 3 y = 10

x = \frac{47}{27}, y = - \frac{4}{27}

Solution steps

[x + 5 y = 1 6 x + 3 y = 10]

Isolate

x

for

x + 5 y = 1 : x = 1 - 5 y

Substitute

x = 1 - 5 y

[6 (1 - 5 y) + 3 y = 10]

Simplify

[6 - 27 y = 10]

Isolate

y

for

6 - 27 y = 10 : y = - \frac{4}{27}

For

x = 1 - 5 y

Substitute

y = - \frac{4}{27}

x = 1 - 5 (- \frac{4}{27})

1 - 5 (- \frac{4}{27}) = \frac{47}{27}

x = \frac{47}{27}

The solutions to the system of equations are:

x = \frac{47}{27}, y = - \frac{4}{27}

4 x - 5 y - 20 = 0, 3 x + 5 y - 15 = 0

x + y = 14, 2 x + 2 y = 8

2 x + 3 y = 8, 7 x - 3 y = 1

(\frac{1}{x} - y) + (\frac{1}{x} + y) = 6, (\frac{1}{x} - y) - (\frac{1}{x} + y) = 4

2 x - y = 4, - 6 x + 3 y = 18