What is (x-7)^2=3y,x=0 ?

The solution to (x-7)^2=3y,x=0 is

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(x-7)^2=3y,x=0

(x - 7)^{2} = 3 y, x = 0

(x = 0, y = \frac{49}{3})

Solution steps

[(x - 7)^{2} = 3 y x = 0]

Plug the solutions

x = 0

into

(x - 7)^{2} = 3 y

For

(x - 7)^{2} = 3 y

, subsitute

x

with

0 : y = \frac{49}{3}

Verify solutions by plugging them into the original equations

Therefore, the final solution for

(x - 7)^{2} = 3 y, x = 0

(x = 0, y = \frac{49}{3})

\frac{1}{7} x + \frac{1}{6} y = 3, \frac{1}{2} x - \frac{1}{3} y = 5

3 x + y = 7, 4 x + 3 y = 6

x - 4 y = 2, 0.8 - 3 x + 6 y = - 2.4

x + 2 y = 5, 2 x + y = - 2

3 x + 4 y = 14, 5 x + 2 y = 14