What is 5x-7y-3=2,x-4y+5=0 ?

The solution to 5x-7y-3=2,x-4y+5=0 is x= 55/13 ,y= 30/13

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5x-7y-3=2,x-4y+5=0

5 x - 7 y - 3 = 2, x - 4 y + 5 = 0

x = \frac{55}{13}, y = \frac{30}{13}

Solution steps

[5 x - 7 y - 3 = 2 x - 4 y + 5 = 0]

Isolate

x

for

5 x - 7 y - 3 = 2 : x = \frac{7 y + 5}{5}

Substitute

x = \frac{7 y + 5}{5}

[\frac{7 y + 5}{5} - 4 y + 5 = 0]

Simplify

[\frac{- 13 y + 5}{5} + 5 = 0]

Isolate

y

for

\frac{- 13 y + 5}{5} + 5 = 0 : y = \frac{30}{13}

For

x = \frac{7 y + 5}{5}

Substitute

y = \frac{30}{13}

x = \frac{7 \cdot \frac{30}{13} + 5}{5}

\frac{7 \cdot \frac{30}{13} + 5}{5} = \frac{55}{13}

x = \frac{55}{13}

The solutions to the system of equations are:

x = \frac{55}{13}, y = \frac{30}{13}

4 x - y = 9, 2 x - 3 y = - 23

2 x - y = 2, y - x = 2

4 x - 8 y = - 14, 2 x + 4 y = - 7

2 x + y = 1, 5 x - y = 12

3 x + 3 y = 6, 3 x + 2 y = 4

What is 5x-7y-3=2,x-4y+5=0 ?
The solution to 5x-7y-3=2,x-4y+5=0 is x= 55/13 ,y= 30/13