What is 23x+29y=98,29x+23y=110 ?

The solution to 23x+29y=98,29x+23y=110 is x=3,y=1

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23x+29y=98,29x+23y=110

23 x + 29 y = 98, 29 x + 23 y = 110

x = 3, y = 1

Solution steps

[23 x + 29 y = 98 29 x + 23 y = 110]

Isolate

x

for

23 x + 29 y = 98 : x = \frac{98 - 29 y}{23}

Substitute

x = \frac{98 - 29 y}{23}

[29 \cdot \frac{98 - 29 y}{23} + 23 y = 110]

Simplify

[\frac{2842 - 312 y}{23} = 110]

Isolate

y

for

\frac{2842 - 312 y}{23} = 110 : y = 1

For

x = \frac{98 - 29 y}{23}

Substitute

y = 1

x = \frac{98 - 29 \cdot 1}{23}

\frac{98 - 29 \cdot 1}{23} = 3

x = 3

The solutions to the system of equations are:

x = 3, y = 1

4 x + 6 y = 12, 2 x + 3 y = 6

101 x + 99 y = 30, 199 x + 101 y = 299

2 x + 3 y = 5, 3 x - 2 y = 1

3 x + y = 4, 4 x + 2 y = 3

2 x - 3 y = 14, 6 x + 4 y = 16

What is 23x+29y=98,29x+23y=110 ?
The solution to 23x+29y=98,29x+23y=110 is x=3,y=1