What is (2a-1)x+3y-5=3,x+(b-1)y-2=0 ?

The solution to (2a-1)x+3y-5=3,x+(b-1)y-2=0 is

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(2a-1)x+3y-5=3,x+(b-1)y-2=0

(2 a - 1) x + 3 y - 5 = 3, x + (b - 1) y - 2 = 0

(x = \frac{- 8 b + 14}{2 a + b - 2 ab + 2}, y = \frac{2 ( - 2 a + 5 )}{2 a - 2 ab + b + 2})

Solution steps

[(2 a - 1) x + 3 y - 5 = 3 x + (b - 1) y - 2 = 0]

Isolate

y

for

(2 a - 1) x + 3 y - 5 = 3 : y = \frac{x - 2 a x + 8}{3}

Plug the solutions

y = \frac{x - 2 a x + 8}{3}

into

x + (- 1 + b) y - 2 = 0

For

x + (- 1 + b) y - 2 = 0

, subsitute

y

with

\frac{x - 2 a x + 8}{3} : x = \frac{- 8 b + 14}{2 a + b - 2 ab + 2}; a \neq = \frac{- b - 2}{2 ( 1 - b )}

Plug the solutions

x = \frac{- 8 b + 14}{2 a + b - 2 ab + 2}

into

(2 a - 1) x + 3 y - 5 = 3

For

(2 a - 1) x + 3 y - 5 = 3

, subsitute

x

with

\frac{- 8 b + 14}{2 a + b - 2 ab + 2} : y = \frac{2 ( - 2 a + 5 )}{2 a - 2 ab + b + 2}

Verify solutions by plugging them into the original equations

Therefore, the final solution for

(2 a - 1) x + 3 y - 5 = 3, x + (b - 1) y - 2 = 0

(x = \frac{- 8 b + 14}{2 a + b - 2 ab + 2}, y = \frac{2 ( - 2 a + 5 )}{2 a - 2 ab + b + 2})

3 x - y = 64, 5 x - 4 y = 14

2 x + y + z = 4, x + y + 2 z = 4, x - y - z = - 1

\frac{4}{3} x - y = 2, 2 x - y = 3

5 x + 2 y = 13, 2 x + 6 y = 26

2 x = 18 - 4 y, 3 x = 7 y - 12

What is (2a-1)x+3y-5=3,x+(b-1)y-2=0 ?
The solution to (2a-1)x+3y-5=3,x+(b-1)y-2=0 is