What is 3x-4y=7,2x+5y=18 ?

The solution to 3x-4y=7,2x+5y=18 is x= 107/23 ,y= 40/23

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3x-4y=7,2x+5y=18

3 x - 4 y = 7, 2 x + 5 y = 18

x = \frac{107}{23}, y = \frac{40}{23}

Solution steps

[3 x - 4 y = 7 2 x + 5 y = 18]

Isolate

x

for

3 x - 4 y = 7 : x = \frac{7 + 4 y}{3}

Substitute

x = \frac{7 + 4 y}{3}

[2 \cdot \frac{7 + 4 y}{3} + 5 y = 18]

Simplify

[\frac{14 + 23 y}{3} = 18]

Isolate

y

for

\frac{14 + 23 y}{3} = 18 : y = \frac{40}{23}

For

x = \frac{7 + 4 y}{3}

Substitute

y = \frac{40}{23}

x = \frac{7 + 4 \cdot \frac{40}{23}}{3}

\frac{7 + 4 \cdot \frac{40}{23}}{3} = \frac{107}{23}

x = \frac{107}{23}

The solutions to the system of equations are:

x = \frac{107}{23}, y = \frac{40}{23}

o = 40, s = 6

y - 2 x = 0, y + x = 3

2 x + 5 y = - 11, 4 x + 10 y = - 22

x - y = 9, 6 x + 4 y = 18

x + y = 97, 2 x + y = 132

What is 3x-4y=7,2x+5y=18 ?
The solution to 3x-4y=7,2x+5y=18 is x= 107/23 ,y= 40/23