What is 2x+4y+8z=0,x+2y+3y=0,x=0 ?

The solution to 2x+4y+8z=0,x+2y+3y=0,x=0 is x=0,y=0,z=0

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2x+4y+8z=0,x+2y+3y=0,x=0

2 x + 4 y + 8 z = 0, x + 2 y + 3 y = 0, x = 0

x = 0, y = 0, z = 0

Solution steps

2 x + 4 y + 8 z = 0 x + 2 y + 3 y = 0 x = 0

Substitute

x = 0

[0 + 2 y + 3 y = 0 2 \cdot 0 + 4 y + 8 z = 0]

Simplify

[5 y = 0 4 y + 8 z = 0]

Isolate

y

for

5 y = 0 : y = 0

Substitute

y = 0

[4 \cdot 0 + 8 z = 0]

Simplify

[8 z = 0]

Isolate

z

for

8 z = 0 : z = 0

The solutions to the system of equations are:

x = 0, y = 0, z = 0

\frac{( 2 x + 5 y )}{( x y )} = 6, \frac{( 4 x - 5 y )}{( x y )} = - 3

2 x + y = 10, y = 3 x

x + y + z = 10, 3 x + 2 y + z = 1, 9 z = 2 x

2 x + 100 = 2, y^{0.2} y = x + 250

8 x - 5 y = 1, 2 y = 3 x - 13

What is 2x+4y+8z=0,x+2y+3y=0,x=0 ?
The solution to 2x+4y+8z=0,x+2y+3y=0,x=0 is x=0,y=0,z=0