What is 4a=5b,11b=15c ?

The solution to 4a=5b,11b=15c is a=(75c)/(44),b=(15c)/(11)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4a=5b,11b=15c

4 a = 5 b, 11 b = 15 c

a = \frac{75 c}{44}, b = \frac{15 c}{11}

Solution steps

[4 a = 5 b 11 b = 15 c]

Isolate

a

for

4 a = 5 b : a = \frac{5 b}{4}

[11 b = 15 c]

Isolate

b

for

11 b = 15 c : b = \frac{15 c}{11}

For

a = \frac{5 b}{4}

Expressing

a

in terms of

c

a = \frac{5 \cdot \frac{15 c}{11}}{4}

Simplify

\frac{5 \cdot \frac{15 c}{11}}{4} : \frac{75 c}{44}

a = \frac{75 c}{44}

The solutions to the system of equations are:

a = \frac{75 c}{44}, b = \frac{15 c}{11}

2 x + 5 y - 2 = 0, e^{3} x + 5 y - 28 = 0

x - 65 x^{3} y = - 1, y = 4

(x) = 4, x - 12 f (x) - 1 (x) = x

- 3 x + y = 1, 2 - y + 9 x = 0

r = 9, a = 1, m = 7

What is 4a=5b,11b=15c ?
The solution to 4a=5b,11b=15c is a=(75c)/(44),b=(15c)/(11)