What is 2j+s=14,3s+j=270 ?

The solution to 2j+s=14,3s+j=270 is s= 526/5 ,j=-228/5

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2j+s=14,3s+j=270

2 j + s = 14, 3 s + j = 270

s = \frac{526}{5}, j = - \frac{228}{5}

Solution steps

[2 j + s = 14 3 s + j = 270]

Isolate

j

for

2 j + s = 14 : j = \frac{14 - s}{2}

Substitute

j = \frac{14 - s}{2}

[3 s + \frac{14 - s}{2} = 270]

Simplify

[\frac{14 + 5 s}{2} = 270]

Isolate

s

for

\frac{14 + 5 s}{2} = 270 : s = \frac{526}{5}

For

j = \frac{14 - s}{2}

Substitute

s = \frac{526}{5}

j = \frac{14 - \frac{526}{5}}{2}

\frac{14 - \frac{526}{5}}{2} = - \frac{228}{5}

j = - \frac{228}{5}

The solutions to the system of equations are:

s = \frac{526}{5}, j = - \frac{228}{5}

2 x - 5 y = 3, 3 x + 2 y = 14

2 x - 25 y = 17, 15 y - x = - 6

5 x + y = 22, 3 x - y = 14

2 x + y = 1, 5 x - y = 6

x + y = 3, 2 x + 5 y = 12

What is 2j+s=14,3s+j=270 ?
The solution to 2j+s=14,3s+j=270 is s= 526/5 ,j=-228/5