What is factor (2x^2-4x-16)/(x-4) ?

The solution to factor (2x^2-4x-16)/(x-4) is 2(x+2)

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factor (2x^2-4x-16)/(x-4)

factor

\frac{2 x ^{2} - 4 x - 16}{x - 4}

2 (x + 2)

Solution steps

\frac{2 x ^{2} - 4 x - 16}{x - 4}

Factor

2 x^{2} - 4 x - 16 : 2 (x + 2) (x - 4)

= \frac{2 ( x + 2 ) ( x - 4 )}{x - 4}

Cancel the common factor:

x - 4

= 2 (x + 2)

- 25 z + 1 + 35 z = 10 z + 1

- (9)^{2}

5 - \frac{5}{4}

9 \cdot 9

18 c g + 4 f g + 6 c f g

What is factor (2x^2-4x-16)/(x-4) ?
The solution to factor (2x^2-4x-16)/(x-4) is 2(x+2)