What is 6x=2,y+93x+4y=12 ?

The solution to 6x=2,y+93x+4y=12 is x= 1/3 ,y=-19/5

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6x=2,y+93x+4y=12

6 x = 2, y + 93 x + 4 y = 12

x = \frac{1}{3}, y = - \frac{19}{5}

Solution steps

[6 x = 2 y + 93 x + 4 y = 12]

Isolate

x

for

6 x = 2 : x = \frac{1}{3}

Substitute

x = \frac{1}{3}

[y + 93 \cdot \frac{1}{3} + 4 y = 12]

Simplify

[5 y + 31 = 12]

Isolate

y

for

5 y + 31 = 12 : y = - \frac{19}{5}

The solutions to the system of equations are:

x = \frac{1}{3}, y = - \frac{19}{5}

x + 4 = 1, 4 x - y = - 4

2 \frac{x}{3} - \frac{3}{4} = 1, \frac{1}{8} y - \frac{5}{6} x = 2

4 x - y = 2, 3 x + 2 y = 7

2 x + y = 1, 8 x - 3 y = - 33

3 x + 2 y = 28, 4 x - 2 y = 0