What is 31x+47y=15,47x+31y=63 ?

The solution to 31x+47y=15,47x+31y=63 is x=2,y=-1

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31x+47y=15,47x+31y=63

31 x + 47 y = 15, 47 x + 31 y = 63

x = 2, y = - 1

Solution steps

[31 x + 47 y = 15 47 x + 31 y = 63]

Isolate

x

for

31 x + 47 y = 15 : x = \frac{15 - 47 y}{31}

Substitute

x = \frac{15 - 47 y}{31}

[47 \cdot \frac{15 - 47 y}{31} + 31 y = 63]

Simplify

[\frac{705 - 1248 y}{31} = 63]

Isolate

y

for

\frac{705 - 1248 y}{31} = 63 : y = - 1

For

x = \frac{15 - 47 y}{31}

Substitute

y = - 1

x = \frac{15 - 47 ( - 1 )}{31}

\frac{15 - 47 ( - 1 )}{31} = 2

x = 2

The solutions to the system of equations are:

x = 2, y = - 1

3 x + 2 y = 8, 0.752 x + 4 y = 8.5

5 x + 7 y = 1, - 3 x + 4 y = - 2 y

y d^{3} x + 5 y = 55, x = 2

2 x + 5 y = 4, 3 x + 4 y = 2

4 x + 2 y = - 8, - x - 0.5 y = 2

What is 31x+47y=15,47x+31y=63 ?
The solution to 31x+47y=15,47x+31y=63 is x=2,y=-1