What are the solutions to the equation r^2+8r+17=0 ?

The solutions to the equation r^2+8r+17=0 are r=-4+i,r=-4-i

Find the zeros of r^2+8r+17=0

The zeros of r^2+8r+17=0 are r=-4+i,r=-4-i

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r^{2} + 8 r + 17 = 0

r = - 4 + i, r = - 4 - i

Solution steps

r^{2} + 8 r + 17 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 17}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 17 : 2 i

r_{1, 2} = \frac{- 8 \pm 2 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 8 + 2 i}{2 \cdot 1}, r_{2} = \frac{- 8 - 2 i}{2 \cdot 1}

r = \frac{- 8 + 2 i}{2 \cdot 1} : - 4 + i

r = \frac{- 8 - 2 i}{2 \cdot 1} : - 4 - i

The solutions to the quadratic equation are:

r = - 4 + i, r = - 4 - i

\frac{6 2}{2}

x^{2} + 2 x - 288 = 0

94

\frac{x ^{- 2}}{y}

\frac{x}{6} - 2 = - 3

What are the solutions to the equation r^2+8r+17=0 ?
The solutions to the equation r^2+8r+17=0 are r=-4+i,r=-4-i
Find the zeros of r^2+8r+17=0
The zeros of r^2+8r+17=0 are r=-4+i,r=-4-i