What is 4x+2y+3z=8,3x+4y+2z=-1,2x-y+5z=3 ?

The solution to 4x+2y+3z=8,3x+4y+2z=-1,2x-y+5z=3 is x=5,y=-3,z=-2

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4x+2y+3z=8,3x+4y+2z=-1,2x-y+5z=3

4 x + 2 y + 3 z = 8, 3 x + 4 y + 2 z = - 1, 2 x - y + 5 z = 3

x = 5, y = - 3, z = - 2

Solution steps

4 x + 2 y + 3 z = 8 3 x + 4 y + 2 z = - 1 2 x - y + 5 z = 3

Isolate

x

for

4 x + 2 y + 3 z = 8 : x = \frac{8 - 2 y - 3 z}{4}

Substitute

x = \frac{8 - 2 y - 3 z}{4}

[3 \cdot \frac{8 - 2 y - 3 z}{4} + 4 y + 2 z = - 1 2 \cdot \frac{8 - 2 y - 3 z}{4} - y + 5 z = 3]

Simplify

[\frac{10 y - z + 24}{4} = - 1 \frac{- 4 y + 7 z + 8}{2} = 3]

Isolate

y

for

\frac{10 y - z + 24}{4} = - 1 : y = \frac{z - 28}{10}

Substitute

y = \frac{z - 28}{10}

[\frac{- 4 \cdot \frac{z - 28}{10} + 7 z + 8}{2} = 3]

Simplify

[\frac{33 z + 96}{10} = 3]

Isolate

z

for

\frac{33 z + 96}{10} = 3 : z = - 2

For

y = \frac{z - 28}{10}

Substitute

z = - 2

y = \frac{- 2 - 28}{10}

\frac{- 2 - 28}{10} = - 3

y = - 3

For

x = \frac{8 - 2 y - 3 z}{4}

Substitute

y = - 3, z = - 2

x = \frac{8 - 2 ( - 3 ) - 3 ( - 2 )}{4}

\frac{8 - 2 ( - 3 ) - 3 ( - 2 )}{4} = 5

x = 5

The solutions to the system of equations are:

x = 5, y = - 3, z = - 2

2 x + 3 y = 1, 4 - x + 5 y = - 7

x - y = - 1, - 2 x - y = 0

5 x - 3 y = 14, 3 x - 5 y = 2

2 x - y = 1, y - 5 x = 2

3 x + 2 y = 1, 2 x - y + 1 = 0

What is 4x+2y+3z=8,3x+4y+2z=-1,2x-y+5z=3 ?
The solution to 4x+2y+3z=8,3x+4y+2z=-1,2x-y+5z=3 is x=5,y=-3,z=-2