What is 3x+6y=39,0x+3y=1300 ?

The solution to 3x+6y=39,0x+3y=1300 is x=-2561/3 ,y= 1300/3

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3x+6y=39,0x+3y=1300

3 x + 6 y = 39, 0 x + 3 y = 1300

x = - \frac{2561}{3}, y = \frac{1300}{3}

Solution steps

[3 x + 6 y = 39 0 \cdot x + 3 y = 1300]

Isolate

x

for

3 x + 6 y = 39 : x = 13 - 2 y

Substitute

x = 13 - 2 y

[0 \cdot (13 - 2 y) + 3 y = 1300]

Simplify

[3 y = 1300]

Isolate

y

for

3 y = 1300 : y = \frac{1300}{3}

For

x = 13 - 2 y

Substitute

y = \frac{1300}{3}

x = 13 - 2 \cdot \frac{1300}{3}

13 - 2 \cdot \frac{1300}{3} = - \frac{2561}{3}

x = - \frac{2561}{3}

The solutions to the system of equations are:

x = - \frac{2561}{3}, y = \frac{1300}{3}

(a) x + 2 y + 3 z = 4, - x + 4 y - 5 z = - 2 x, 2 x - 3 y + 4 z = 27

7 x - 4 y = 1, 7 x - 2 y = 53

x + y = 3, x + z = 4, y + z = - 3

x - (- 2) y + 11 = 3, x - 6 y + 33 = 0

3 x + 2 y = 2, x - y = 9

What is 3x+6y=39,0x+3y=1300 ?
The solution to 3x+6y=39,0x+3y=1300 is x=-2561/3 ,y= 1300/3