What is 20x+10y=50,0y^{40}x-50y=300 ?

The solution to 20x+10y=50,0y^{40}x-50y=300 is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

20x+10y=50,0y^{40}x-50y=300

20 x + 10 y = 50, 0 y^{40} x - 50 y = 300

(x = \frac{11}{2}, y = - 6)

Solution steps

[20 x + 10 y = 50 0 \cdot y^{40} x - 50 y = 300]

Solve

0 y^{40} x - 50 y = 300 : y = - 6

For

20 x + 10 y = 50

, subsitute

y

with

- 6

20 x + 10 (- 6) = 50

20 x + 10 (- 6) = 50 : x = \frac{11}{2}

Verify solutions by plugging them into the original equations

Therefore, the final solution for

20 x + 10 y = 50, 0 y^{40} x - 50 y = 300

(x = \frac{11}{2}, y = - 6)

3 x - 2 y = 10, 2 x + 3 y = 10

4 x - 11 y = - 3, 2 x + 5 y = 21

x + y + z = 9, 2 x - 3 y + 4 z = 13, 3 x + 4 y + 5 z = 40

a = 2, m = 3

x - y = 1, x^{3} - y^{3} = 7

What is 20x+10y=50,0y^{40}x-50y=300 ?
The solution to 20x+10y=50,0y^{40}x-50y=300 is