What is x^2+y^2=2,5yx+y-1=0 ?

The solution to x^2+y^2=2,5yx+y-1=0 is

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Popular >

x^2+y^2=2,5yx+y-1=0

Solution

x^{2} + y^{2} = 2, 5 y x + y - 1 = 0

Solution

x = - 0.34584 \dots, x = 1.40873 \dots, x = - 1.40443 \dots, x = - 0.05845 \dots, y = - 1.37127 \dots y = 0.12432 \dots y = - 0.16605 \dots y = 1.41300 \dots

Solution steps

[x^{2} + y^{2} = 2 5 y x + y - 1 = 0]

Isolate

x

for

5 y x + y - 1 = 0 : x = \frac{- y + 1}{5 y}; y \neq = 0

Plug the solutions

x = \frac{- y + 1}{5 y}

into

x^{2} + y^{2} = 2

For

x^{2} + y^{2} = 2

, subsitute

x

with

\frac{- y + 1}{5 y} : y \approx - 1.37127 \dots, y \approx 0.12432 \dots, y \approx - 0.16605 \dots, y \approx 1.41300 \dots

Plug the solutions

y = - 1.37127 \dots, y = 0.12432 \dots, y = - 0.16605 \dots, y = 1.41300 \dots

into

5 y x + y - 1 = 0

For

5 y x + y - 1 = 0

, subsitute

y

with

- 1.37127 \dots : x = - 0.34584 \dots

For

5 y x + y - 1 = 0

, subsitute

y

with

0.12432 \dots : x = 1.40873 \dots

For

5 y x + y - 1 = 0

, subsitute

y

with

- 0.16605 \dots : x = - 1.40443 \dots

For

5 y x + y - 1 = 0

, subsitute

y

with

1.41300 \dots : x = - 0.05845 \dots

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

x^{2} + y^{2} = 2, 5 y x + y - 1 = 0

are

x = - 0.34584 \dots, x = 1.40873 \dots, x = - 1.40443 \dots, x = - 0.05845 \dots, y = - 1.37127 \dots y = 0.12432 \dots y = - 0.16605 \dots y = 1.41300 \dots

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x + y = 2, x (x - y) = 12

x^2+y^2=2,6y=3-2x

x^{2} + y^{2} = 2, 6 y = 3 - 2 x

x-3y=6,x-3y=4

x - 3 y = 6, x - 3 y = 4

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x^{2} - 28 x + 195 = 0, y^{2} - 35 y + 306 = 0

-2x+y=1,2x-y=2

- 2 x + y = 1, 2 x - y = 2

Frequently Asked Questions (FAQ)

What is x^2+y^2=2,5yx+y-1=0 ?
The solution to x^2+y^2=2,5yx+y-1=0 is