What is 56x^2-x=11,5y^2+8y+1=0 ?

The solution to 56x^2-x=11,5y^2+8y+1=0 is

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56x^2-x=11,5y^2+8y+1=0

56 x^{2} - x = 11, 5 y^{2} + 8 y + 1 = 0

x = \frac{1 + 2465}{112}, x = \frac{1 - 2465}{112}, x = \frac{1 + 2465}{112}, x = \frac{1 - 2465}{112}, y = \frac{- 4 + 11}{5} y = \frac{- 4 + 11}{5} y = - \frac{4 + 11}{5} y = - \frac{4 + 11}{5}

Solution steps

[56 x^{2} - x = 11 5 y^{2} + 8 y + 1 = 0]

Solve

5 y^{2} + 8 y + 1 = 0 : y = \frac{- 4 + 11}{5}, y = - \frac{4 + 11}{5}

Plug the solutions

y = \frac{- 4 + 11}{5}, y = - \frac{4 + 11}{5}

into

56 x^{2} - x = 11

For

56 x^{2} - x = 11

, subsitute

y

with

\frac{- 4 + 11}{5} : x = \frac{1 + 2465}{112}, x = \frac{1 - 2465}{112}

For

56 x^{2} - x = 11

, subsitute

y

with

- \frac{4 + 11}{5} : x = \frac{1 + 2465}{112}, x = \frac{1 - 2465}{112}

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

56 x^{2} - x = 11, 5 y^{2} + 8 y + 1 = 0

are

x = \frac{1 + 2465}{112}, x = \frac{1 - 2465}{112}, x = \frac{1 + 2465}{112}, x = \frac{1 - 2465}{112}, y = \frac{- 4 + 11}{5} y = \frac{- 4 + 11}{5} y = - \frac{4 + 11}{5} y = - \frac{4 + 11}{5}

x + y = 2, x^{5} + y^{5} = 82

x + y - z = 17, 0 x + z - y = 130

3 x^{2} - 3 + y^{2} = 0, 2 x y = 0

1 x^{2} + x - 12 = 0, y^{2} - 5 y + 6 = 0

4 x y - 2 x^{2} = - 6, 6 x + 3 y = - 6