What is ((a+1))/5 =1, 6/((b+2))=c ?

The solution to ((a+1))/5 =1, 6/((b+2))=c is

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((a+1))/5 =1, 6/((b+2))=c

\frac{( a + 1 )}{5} = 1, \frac{6}{( b + 2 )} = c

(a = 4, b \in R, c = \frac{6}{b + 2})

Solution steps

[\frac{( a + 1 )}{5} = 1 \frac{6}{( b + 2 )} = c]

Solve

\frac{( a + 1 )}{5} = 1 : a = 4

Solve

\frac{6}{( b + 2 )} = c

for

a = 4 : (a = 4, b \in R, c = \frac{6}{b + 2})

Verify solutions by plugging them into the original equations

Therefore, the final solution for

\frac{( a + 1 )}{5} = 1, \frac{6}{( b + 2 )} = c

(a = 4, b \in R, c = \frac{6}{b + 2})

x^{2} = 23 x + y, y^{2} = 23 x + y

x^{2} + (y - 1) 2 = 13, 2 x + 3 y = 3

x + y = 1, x^{2} - 2 x + 3 y = - 1

x + 2 y = 1, 2 x^{2} + 2 y = 42

x + 2 y = 2, x + 2 y = 6

What is ((a+1))/5 =1, 6/((b+2))=c ?
The solution to ((a+1))/5 =1, 6/((b+2))=c is