What is x^2-x-sqrt(3x)+sqrt(3)=0,y^2-3y+2=0 ?

The solution to x^2-x-sqrt(3x)+sqrt(3)=0,y^2-3y+2=0 is

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x^2-x-sqrt(3x)+sqrt(3)=0,y^2-3y+2=0

x^{2} - x - 3 x + 3 = 0, y^{2} - 3 y + 2 = 0

x = 1, x = 0.89100 \dots, x = 1, x = 0.89100 \dots, y = 1 y = 1 y = 2 y = 2

Solution steps

[x^{2} - x - 3 x + 3 = 0 y^{2} - 3 y + 2 = 0]

Solve

y^{2} - 3 y + 2 = 0 : y = 1, y = 2

For

x^{2} - x - 3 x + 3 = 0

, subsitute

y

with

1 : x = 1, x \approx 0.89100 \dots

For

x^{2} - x - 3 x + 3 = 0

, subsitute

y

with

2 : x = 1, x \approx 0.89100 \dots

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

x^{2} - x - 3 x + 3 = 0, y^{2} - 3 y + 2 = 0

are

x = 1, x = 0.89100 \dots, x = 1, x = 0.89100 \dots, y = 1 y = 1 y = 2 y = 2

t^{2} y = 4 t, x = 2

6^{b} = 8 4^{c}, 1 4^{a} = 3

a + b = 4, a \cdot b = 1 a^{3} + b^{3}

3 x - 2 y = 6, x y = 12

x - y = 8, x - y = 15

What is x^2-x-sqrt(3x)+sqrt(3)=0,y^2-3y+2=0 ?
The solution to x^2-x-sqrt(3x)+sqrt(3)=0,y^2-3y+2=0 is