What is 2x-y=10,3x+y^2=22 ?

The solution to 2x-y=10,3x+y^2=22 is

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2x-y=10,3x+y^2=22

2 x - y = 10, 3 x + y^{2} = 22

(x = 6, x = \frac{13}{4}, y = 2 y = - \frac{7}{2})

Solution steps

[2 x - y = 10 3 x + y^{2} = 22]

Isolate

x

for

2 x - y = 10 : x = \frac{10 + y}{2}

Plug the solutions

x = \frac{10 + y}{2}

into

3 x + y^{2} = 22

For

3 x + y^{2} = 22

, subsitute

x

with

\frac{10 + y}{2} : y = 2, y = - \frac{7}{2}

Plug the solutions

y = 2, y = - \frac{7}{2}

into

2 x - y = 10

For

2 x - y = 10

, subsitute

y

with

2 : x = 6

For

2 x - y = 10

, subsitute

y

with

- \frac{7}{2} : x = \frac{13}{4}

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

2 x - y = 10, 3 x + y^{2} = 22

are

(x = 6, x = \frac{13}{4}, y = 2 y = - \frac{7}{2})

f (x) = 2, - x - x^{3} = 0

3 x^{2} + 3 y^{2} = 7, x^{3} + y^{3} = 3

x^{2} + 3 x + 2 = 0, y^{2} + 7 y + 12 = 0

4 x = 8, x - y = 6

8 x + y = 13, 8 x + y = 13