What is 9y^2-45y+56=4,x^2-17y+18=0 ?

The solution to 9y^2-45y+56=4,x^2-17y+18=0 is

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9y^2-45y+56=4,x^2-17y+18=0

9 y^{2} - 45 y + 56 = 4, x^{2} - 17 y + 18 = 0

x = \frac{17 ( 15 + 17 )}{6} - 18, x = - \frac{17 ( 15 + 17 )}{6} - 18, x = \frac{17 ( 15 - 17 )}{6} - 18, x = - \frac{17 ( 15 - 17 )}{6} - 18, y = \frac{15 + 17}{6} y = \frac{15 + 17}{6} y = \frac{15 - 17}{6} y = \frac{15 - 17}{6}

Solution steps

[9 y^{2} - 45 y + 56 = 4 x^{2} - 17 y + 18 = 0]

Solve

9 y^{2} - 45 y + 56 = 4 : y = \frac{15 + 17}{6}, y = \frac{15 - 17}{6}

Plug the solutions

y = \frac{15 + 17}{6}, y = \frac{15 - 17}{6}

into

x^{2} - 17 y + 18 = 0

For

x^{2} - 17 y + 18 = 0

, subsitute

y

with

\frac{15 + 17}{6} : x = \frac{17 ( 15 + 17 )}{6} - 18, x = - \frac{17 ( 15 + 17 )}{6} - 18

For

x^{2} - 17 y + 18 = 0

, subsitute

y

with

\frac{15 - 17}{6} : x = \frac{17 ( 15 - 17 )}{6} - 18, x = - \frac{17 ( 15 - 17 )}{6} - 18

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

9 y^{2} - 45 y + 56 = 4, x^{2} - 17 y + 18 = 0

are

x = \frac{17 ( 15 + 17 )}{6} - 18, x = - \frac{17 ( 15 + 17 )}{6} - 18, x = \frac{17 ( 15 - 17 )}{6} - 18, x = - \frac{17 ( 15 - 17 )}{6} - 18, y = \frac{15 + 17}{6} y = \frac{15 + 17}{6} y = \frac{15 - 17}{6} y = \frac{15 - 17}{6}

x^{2} + 3 y^{2} = 12, x - y = 2

4 a + b = 6, 4 a + b = 1

b = 4 a, c = 5

x + 2 y = 8, - x - 2 y = - 8

x y^{3} = - 108, (x + y) y = - 3

What is 9y^2-45y+56=4,x^2-17y+18=0 ?
The solution to 9y^2-45y+56=4,x^2-17y+18=0 is