What is f(x)=x^2-2x+3,f(x)=-6x ?

The solution to f(x)=x^2-2x+3,f(x)=-6x is

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f(x)=x^2-2x+3,f(x)=-6x

f (x) = x^{2} - 2 x + 3, f (x) = - 6 x

(x = - 1, x = - 3, f = 6 f = 18)

Solution steps

[f = x^{2} - 2 x + 3 f = - 6 x]

Subtract the equations

f = x^{2} - 2 x + 3

f - f = x^{2} - 2 x + 3 - (- 6 x)

Simplify

0 = x^{2} + 4 x + 3

Solve

0 = x^{2} + 4 x + 3 : x = - 1, x = - 3

Plug the solutions

x = - 1, x = - 3

into

f = x^{2} - 2 x + 3

For

f = x^{2} - 2 x + 3

, subsitute

x

with

- 1 : f = 6

For

f = x^{2} - 2 x + 3

, subsitute

x

with

- 3 : f = 18

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

f = x^{2} - 2 x + 3, f = - 6 x

are

(x = - 1, x = - 3, f = 6 f = 18)

f (x) = 5, x + 19 (x) = x^{2} + 2

2 y + x = 1, x^{2} - 2 x + y^{2} - 4 y = 8

x + y = 10, x y = 40

a + b = 30, a - b = 20 \frac{a}{b}

f (x) = 2, x^{2} - 7 x + 3 = 12