What is y-17=x^2-9x,-x+y=1 ?

The solution to y-17=x^2-9x,-x+y=1 is

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y-17=x^2-9x,-x+y=1

y - 17 = x^{2} - 9 x, - x + y = 1

(x = 8, x = 2, y = 9 y = 3)

Solution steps

[y - 17 = x^{2} - 9 x - x + y = 1]

Subtract the equations

y - 17 = x^{2} - 9 x

y - 17 - (- x + y) = x^{2} - 9 x - 1

Simplify

x - 17 = x^{2} - 9 x - 1

Solve

x - 17 = x^{2} - 9 x - 1 : x = 8, x = 2

Plug the solutions

x = 8, x = 2

into

y - 17 = x^{2} - 9 x

For

y - 17 = x^{2} - 9 x

, subsitute

x

with

8 : y = 9

For

y - 17 = x^{2} - 9 x

, subsitute

x

with

2 : y = 3

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

y - 17 = x^{2} - 9 x, - x + y = 1

are

(x = 8, x = 2, y = 9 y = 3)

a = \frac{81}{3 ^{3}} - x y, b = 2^{3} - x y

18 x - 24 y = 6, 18 x - 24 y = - 45

y - 6 = x^{2} - 3 x, x + 2 y = 2

3 x + y = 4, 2 y^{5} x + 3 y = 78

x^{2} - 31 x + 184 = 0, y^{2} - 49 y + 600 = 0