What is x+y=1,7x^2+y^2=13^2 ?

The solution to x+y=1,7x^2+y^2=13^2 is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x+y=1,7x^2+y^2=13^2

x + y = 1, 7 x^{2} + y^{2} = 1 3^{2}

(x = 1 - \frac{7 + 1345}{8}, x = 1 - \frac{7 - 1345}{8}, y = \frac{7 + 1345}{8} y = \frac{7 - 1345}{8})

Solution steps

[x + y = 1 7 x^{2} + y^{2} = 1 3^{2}]

Isolate

x

for

x + y = 1 : x = 1 - y

Plug the solutions

x = 1 - y

into

7 x^{2} + y^{2} = 1 3^{2}

For

7 x^{2} + y^{2} = 1 3^{2}

, subsitute

x

with

1 - y : y = \frac{7 + 1345}{8}, y = \frac{7 - 1345}{8}

Plug the solutions

y = \frac{7 + 1345}{8}, y = \frac{7 - 1345}{8}

into

x + y = 1

For

x + y = 1

, subsitute

y

with

\frac{7 + 1345}{8} : x = 1 - \frac{7 + 1345}{8}

For

x + y = 1

, subsitute

y

with

\frac{7 - 1345}{8} : x = 1 - \frac{7 - 1345}{8}

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

x + y = 1, 7 x^{2} + y^{2} = 1 3^{2}

are

(x = 1 - \frac{7 + 1345}{8}, x = 1 - \frac{7 - 1345}{8}, y = \frac{7 + 1345}{8} y = \frac{7 - 1345}{8})

a + b + z = 5, 3 z - x - y = 81

f (x) = x^{2} - 2 x + 3, f (x) = - 2 x \cdot 2

7 y = 2, y^{3} = 2

(x^{y} - y)^{2} + x^{y} - y = 2, x^{2 y} + 3 x^{y} = 10

2 a^{2} = 6 a^{3} - a^{6}, b = 1