What is 2x-y=3,x^2-xy=-4 ?

The solution to 2x-y=3,x^2-xy=-4 is

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2x-y=3,x^2-xy=-4

2 x - y = 3, x^{2} - x y = - 4

(x = - 1, x = 4, y = - 5 y = 5)

Solution steps

[2 x - y = 3 x^{2} - x y = - 4]

Isolate

x

for

2 x - y = 3 : x = \frac{3 + y}{2}

Plug the solutions

x = \frac{3 + y}{2}

into

x^{2} - x y = - 4

For

x^{2} - x y = - 4

, subsitute

x

with

\frac{3 + y}{2} : y = - 5, y = 5

Plug the solutions

y = - 5, y = 5

into

2 x - y = 3

For

2 x - y = 3

, subsitute

y

with

- 5 : x = - 1

For

2 x - y = 3

, subsitute

y

with

5 : x = 4

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

2 x - y = 3, x^{2} - x y = - 4

are

(x = - 1, x = 4, y = - 5 y = 5)

x + 3 y^{2} = 5, 3 x - y = 5 y

(a - b) (a + b) = 16, a + b = 8

f (x) = 0, f (x) = x^{3} - 3 x^{2} + 4

d = 300 m, t = 3 h

c = (a + b) + c, a = 6