What are the solutions to the equation -4x^2+8x+44=16 ?

The solutions to the equation -4x^2+8x+44=16 are x=1-2sqrt(2),x=1+2sqrt(2)

Find the zeros of -4x^2+8x+44=16

The zeros of -4x^2+8x+44=16 are x=1-2sqrt(2),x=1+2sqrt(2)

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- 4 x^{2} + 8 x + 44 = 16

x = 1 - 22, x = 1 + 22

Solution steps

- 4 x^{2} + 8 x + 44 = 16

Move

16

to the left side

- 4 x^{2} + 8 x + 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 4 ) \cdot 28}{2 ( - 4 )}

8^{2} - 4 (- 4) \cdot 28 = 162

x_{1, 2} = \frac{- 8 \pm 16 2}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 8 + 16 2}{2 ( - 4 )}, x_{2} = \frac{- 8 - 16 2}{2 ( - 4 )}

x = \frac{- 8 + 16 2}{2 ( - 4 )} : 1 - 22

x = \frac{- 8 - 16 2}{2 ( - 4 )} : 1 + 22

The solutions to the quadratic equation are:

x = 1 - 22, x = 1 + 22

x y - x z - y w + z w

7 y - 2 (8 y + 1) = 4

3 - 4 y < 12

- 4 - 0

\frac{4 x + 4}{3} < 8

What are the solutions to the equation -4x^2+8x+44=16 ?
The solutions to the equation -4x^2+8x+44=16 are x=1-2sqrt(2),x=1+2sqrt(2)
Find the zeros of -4x^2+8x+44=16
The zeros of -4x^2+8x+44=16 are x=1-2sqrt(2),x=1+2sqrt(2)