What is 8x+(-2a+b-4)=4y,-6x+(a-b+2)y+9=0 ?

The solution to 8x+(-2a+b-4)=4y,-6x+(a-b+2)y+9=0 is No Solution

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8x+(-2a+b-4)=4y,-6x+(a-b+2)y+9=0

8 x + (- 2 a + b - 4) = 4 y, - 6 x + (a - b + 2) y + 9 = 0

No Solution

Solution steps

[8 x + (- 2 a + b - 4) = 4 y - 6 x + (a - b + 2) y + 9 = 0]

Isolate

x

for

8 x + (- 2 a + b - 4) = 4 y : x = \frac{4 y + 2 a - b + 4}{8}

Plug the solutions

x = \frac{4 y + 2 a - b + 4}{8}

into

- 6 x + (2 + a - b) y + 9 = 0

For

- 6 x + (2 + a - b) y + 9 = 0

, subsitute

x

with

\frac{4 y + 2 a - b + 4}{8} : y = \frac{6 a - 3 b - 24}{4 ( - 1 + a - b )}; a \neq = b + 1

Plug the solutions

y = \frac{6 a - 3 b - 24}{4 ( - 1 + a - b )}

into

8 x + (- 2 a + b - 4) = 4 y

For

8 x + (- 2 a + b - 4) = 4 y

, subsitute

y

with

\frac{6 a - 3 b - 24}{4 ( - 1 + a - b )} : x = \frac{2 a ^{2} + 8 a - 3 ab + b ^{2} - 6 b - 28}{8 ( - 1 + a - b )}

Verify solutions by plugging them into the original equations

No Solution

3 x y + 2 y^{2} = 5, x y - 3 y^{2} = - 57

x - x^{2} y = x - 2, y = 2

x + y = 7, x y^{2} x - 3 y + x y = 0

- 2 x^{2} y = 4 - x^{2}, y = 9

- x - y = - 3, x^{2} - y = - 1

What is 8x+(-2a+b-4)=4y,-6x+(a-b+2)y+9=0 ?
The solution to 8x+(-2a+b-4)=4y,-6x+(a-b+2)y+9=0 is No Solution