What is 2a^2=3,b+82b^2=3a+8a^2+b^2 ?

The solution to 2a^2=3,b+82b^2=3a+8a^2+b^2 is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2a^2=3,b+82b^2=3a+8a^2+b^2

2 a^{2} = 3, b + 82 b^{2} = 3 a + 8 a^{2} + b^{2}

a = - \frac{3}{2}, a = - \frac{3}{2}, a = \frac{3}{2}, a = \frac{3}{2}, b = \frac{- 1 + 3889 - 486 6}{162} b = \frac{- 1 - 3889 - 486 6}{162} b = \frac{- 1 + 3889 + 486 6}{162} b = \frac{- 1 - 3889 + 486 6}{162}

Solution steps

[2 a^{2} = 3 b + 82 b^{2} = 3 a + 8 a^{2} + b^{2}]

Solve

2 a^{2} = 3 : a = - \frac{3}{2}, a = \frac{3}{2}

For

b + 82 b^{2} = 3 a + 8 a^{2} + b^{2}

, subsitute

a

with

- \frac{3}{2} : b = \frac{- 1 + 3889 - 486 6}{162}, b = \frac{- 1 - 3889 - 486 6}{162}

For

b + 82 b^{2} = 3 a + 8 a^{2} + b^{2}

, subsitute

a

with

\frac{3}{2} : b = \frac{- 1 + 3889 + 486 6}{162}, b = \frac{- 1 - 3889 + 486 6}{162}

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

2 a^{2} = 3, b + 82 b^{2} = 3 a + 8 a^{2} + b^{2}

are

a = - \frac{3}{2}, a = - \frac{3}{2}, a = \frac{3}{2}, a = \frac{3}{2}, b = \frac{- 1 + 3889 - 486 6}{162} b = \frac{- 1 - 3889 - 486 6}{162} b = \frac{- 1 + 3889 + 486 6}{162} b = \frac{- 1 - 3889 + 486 6}{162}

1 x^{2} + 7 x + 12 = 0, 11 \cdot 2 y^{2} + 17 y + 35 = 0

7 x - 2 \frac{y}{x} y = 5, 8 x + 7 \frac{y}{x} y = 15

3 x + y = 1, 3 x + y = 17

x + 2 y = 0, x + 2 y = 5

x^{2} + y^{2} = 26, x + y = 4

What is 2a^2=3,b+82b^2=3a+8a^2+b^2 ?
The solution to 2a^2=3,b+82b^2=3a+8a^2+b^2 is