What is x-1=1,x^3-y^3=7 ?

The solution to x-1=1,x^3-y^3=7 is

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x-1=1,x^3-y^3=7

x - 1 = 1, x^{3} - y^{3} = 7

x = 2, x = 2, x = 2, y = 1 y = - \frac{1}{2} + \frac{3}{2} i y = - \frac{1}{2} - \frac{3}{2} i

Solution steps

[x - 1 = 1 x^{3} - y^{3} = 7]

Solve

x - 1 = 1 : x = 2

Plug the solutions

x = 2

into

x^{3} - y^{3} = 7

For

x^{3} - y^{3} = 7

, subsitute

x

with

2 : y = 1, y = - \frac{1}{2} + \frac{3}{2} i, y = - \frac{1}{2} - \frac{3}{2} i

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

x - 1 = 1, x^{3} - y^{3} = 7

are

x = 2, x = 2, x = 2, y = 1 y = - \frac{1}{2} + \frac{3}{2} i y = - \frac{1}{2} - \frac{3}{2} i

y = 2 x^{2} + z^{2}, y = 6 - 2 x^{2} - z^{2}

\frac{1}{2 ^{x}} + \frac{2}{3 ^{y}} = 10, \frac{3}{2 ^{x}} + \frac{7}{3 ^{y}} = 33

a + b = 27, a \cdot b = 182

x (n) = 1 + 3 x (\frac{n}{2}), x (1) = 0

x + y = 3, x^{3} + y^{3} = 9