What is 8x^4-3y=17,7x-4y=8 ?

The solution to 8x^4-3y=17,7x-4y=8 is

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8x^4-3y=17,7x-4y=8

8 x^{4} - 3 y = 17, 7 x - 4 y = 8

(x = 1.21394 \dots, x = - 0.93426 \dots, y = 0.12439 \dots y = - 3.63497 \dots)

Solution steps

[8 x^{4} - 3 y = 17 7 x - 4 y = 8]

Isolate

x

for

7 x - 4 y = 8 : x = \frac{8 + 4 y}{7}

Plug the solutions

x = \frac{8 + 4 y}{7}

into

8 x^{4} - 3 y = 17

For

8 x^{4} - 3 y = 17

, subsitute

x

with

\frac{8 + 4 y}{7} : y \approx 0.12439 \dots, y \approx - 3.63497 \dots

Plug the solutions

y = 0.12439 \dots, y = - 3.63497 \dots

into

7 x - 4 y = 8

For

7 x - 4 y = 8

, subsitute

y

with

0.12439 \dots : x = 1.21394 \dots

For

7 x - 4 y = 8

, subsitute

y

with

- 3.63497 \dots : x = - 0.93426 \dots

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

8 x^{4} - 3 y = 17, 7 x - 4 y = 8

are

(x = 1.21394 \dots, x = - 0.93426 \dots, y = 0.12439 \dots y = - 3.63497 \dots)

x - y = - 6, x^{2} - y = - 4

6 x^{2} + 7 x - 3 = 0, x_{1} = x_{2}

x - y = 2, 2 x^{2} + 9 y^{2} = 23

a + b = 4, a^{2} + b^{2} = 2

\frac{1}{2} x + \frac{1}{3} y = 2, \frac{5}{x} - 2 y = \frac{17}{3}