What is y^2x+5y=7,3x+2y=5 ?

The solution to y^2x+5y=7,3x+2y=5 is

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y^2x+5y=7,3x+2y=5

y^{2} x + 5 y = 7, 3 x + 2 y = 5

x = 0.89355 \dots, x = 3.27506 \dots, x = - 0.83529 \dots, y = 1.15966 \dots y = - 2.41260 \dots y = 3.75293 \dots

Solution steps

[y^{2} x + 5 y = 7 3 x + 2 y = 5]

Isolate

x

for

3 x + 2 y = 5 : x = \frac{5 - 2 y}{3}

Plug the solutions

x = \frac{5 - 2 y}{3}

into

y^{2} x + 5 y = 7

For

y^{2} x + 5 y = 7

, subsitute

x

with

\frac{5 - 2 y}{3} : y \approx 1.15966 \dots, y \approx - 2.41260 \dots, y \approx 3.75293 \dots

Plug the solutions

y = 1.15966 \dots, y = - 2.41260 \dots, y = 3.75293 \dots

into

3 x + 2 y = 5

For

3 x + 2 y = 5

, subsitute

y

with

1.15966 \dots : x = 0.89355 \dots

For

3 x + 2 y = 5

, subsitute

y

with

- 2.41260 \dots : x = 3.27506 \dots

For

3 x + 2 y = 5

, subsitute

y

with

3.75293 \dots : x = - 0.83529 \dots

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

y^{2} x + 5 y = 7, 3 x + 2 y = 5

are

x = 0.89355 \dots, x = 3.27506 \dots, x = - 0.83529 \dots, y = 1.15966 \dots y = - 2.41260 \dots y = 3.75293 \dots

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