What are the solutions to the equation 8x^2+26x+21=0 ?

The solutions to the equation 8x^2+26x+21=0 are x=-3/2 ,x=-7/4

Find the zeros of 8x^2+26x+21=0

The zeros of 8x^2+26x+21=0 are x=-3/2 ,x=-7/4

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8 x^{2} + 26 x + 21 = 0

x = - \frac{3}{2}, x = - \frac{7}{4}

Decimal Notation

x = - 1.5, x = - 1.75

Solution steps

8 x^{2} + 26 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 \cdot 8 \cdot 21}{2 \cdot 8}

2 6^{2} - 4 \cdot 8 \cdot 21 = 2

x_{1, 2} = \frac{- 26 \pm 2}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 26 + 2}{2 \cdot 8}, x_{2} = \frac{- 26 - 2}{2 \cdot 8}

x = \frac{- 26 + 2}{2 \cdot 8} : - \frac{3}{2}

x = \frac{- 26 - 2}{2 \cdot 8} : - \frac{7}{4}

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = - \frac{7}{4}

125 q^{6} - r^{6} s^{3}

10 x \leq - 7

36 x y^{5} m - 6 x y^{4} m^{6} + 42 x y^{3} m^{4}

\frac{1}{4} - \frac{1}{6} - \frac{1}{9} + \frac{1}{26}

2 (3 x - 4) = 22

What are the solutions to the equation 8x^2+26x+21=0 ?
The solutions to the equation 8x^2+26x+21=0 are x=-3/2 ,x=-7/4
Find the zeros of 8x^2+26x+21=0
The zeros of 8x^2+26x+21=0 are x=-3/2 ,x=-7/4