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Popular >

x^2+x+2>0

Solution

x^{2} + x + 2 > 0

Solution

True for all x

+1

Interval Notation

(- \infty, \infty)

Solution steps

x^{2} + x + 2 > 0

Complete the square

x^{2} + x + 2 : (x + \frac{1}{2})^{2} + \frac{7}{4}

(x + \frac{1}{2})^{2} + \frac{7}{4} > 0

Move

\frac{7}{4}

to the right side

(x + \frac{1}{2})^{2} > - \frac{7}{4}

If n is even,

u^{n} \geq 0

for all

u

True for all x

Popular Examples

x/((x+2))<= 1/x

\frac{x}{( x + 2 )} \leq \frac{1}{x}

((x^2-9))/((3x-x^2-24))<0

\frac{( x ^{2} - 9 )}{( 3 x - x ^{2} - 24 )} < 0

2 x^{2} - 2 x - 1 < 0

((2x))/((2x^2+5x+2))> 1/((x+1))

\frac{( 2 x )}{( 2 x ^{2} + 5 x + 2 )} > \frac{1}{( x + 1 )}

1/(2(3-8x))>20((1-1)/(5x))

\frac{1}{2 ( 3 - 8 x )} > 20 (\frac{1 - 1}{5 x})

Frequently Asked Questions (FAQ)

What is x^2+x+2>0 ?
The solution to x^2+x+2>0 is True for all x