What are the solutions to the equation x^2+3/4 x-1/4 =0 ?

The solutions to the equation x^2+3/4 x-1/4 =0 are x= 1/4 ,x=-1

Find the zeros of x^2+3/4 x-1/4 =0

The zeros of x^2+3/4 x-1/4 =0 are x= 1/4 ,x=-1

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x^{2} + \frac{3}{4} x - \frac{1}{4} = 0

x = \frac{1}{4}, x = - 1

Solution steps

x^{2} + \frac{3}{4} x - \frac{1}{4} = 0

Multiply both sides by

4

4 x^{2} + 3 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 ( - 1 )}{2 \cdot 4}

3^{2} - 4 \cdot 4 (- 1) = 5

x_{1, 2} = \frac{- 3 \pm 5}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 3 + 5}{2 \cdot 4}, x_{2} = \frac{- 3 - 5}{2 \cdot 4}

x = \frac{- 3 + 5}{2 \cdot 4} : \frac{1}{4}

x = \frac{- 3 - 5}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - 1

9 - 5 x = 24

π 3^{2}

9 x^{2} (x^{2} + 3) - (x^{2} + 3)

(\frac{3 m ^{5} r ^{3}}{4 p ^{8}})^{4}

32 x^{3} - 4 x^{2} + 20 x

What are the solutions to the equation x^2+3/4 x-1/4 =0 ?
The solutions to the equation x^2+3/4 x-1/4 =0 are x= 1/4 ,x=-1
Find the zeros of x^2+3/4 x-1/4 =0
The zeros of x^2+3/4 x-1/4 =0 are x= 1/4 ,x=-1