What is ((x+1))/((2x+3))>= 1 ?

The solution to ((x+1))/((2x+3))>= 1 is -2<= x<-3/2

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((x+1))/((2x+3))>= 1

\frac{( x + 1 )}{( 2 x + 3 )} \geq 1

- 2 \leq x < - \frac{3}{2}

Interval Notation

[- 2, - \frac{3}{2})

Decimal Notation

- 2 \leq x < - 1.5

Solution steps

\frac{x + 1}{2 x + 3} \geq 1

Rewrite in standard form

\frac{- x - 2}{2 x + 3} \geq 0

Identify the intervals

- 2 \leq x < - \frac{3}{2}

\frac{4}{( x - 2 ) ^{2}} > 1

5 - [2 x + (x + 2)] < 4

\frac{( ( x - 1 ) ( x + 2 ) )}{( ( x - 3 ) ( x + 3 ) )} < 0

\frac{x}{x - 2} < \frac{1}{x + 3}

x^{3} - 3 x^{2} - 10 x + 24 > 0

What is ((x+1))/((2x+3))>= 1 ?
The solution to ((x+1))/((2x+3))>= 1 is -2<= x<-3/2